[英]Read date from Excel file and get a delta with today's date
I have an excel file with some dates in it. 我有一个excel文件,里面有一些日期。 They're formatted with dd-mm-yyyy
. 它们的格式为dd-mm-yyyy
。 I would like to take each date in that column and get a delta of it with today's date. 我想在该列中记录每个日期,并在今天的日期获得它的增量。
For example, if the Excel file has a date as so: 20-6-2019, it will subtract today's date (16/6/2019) and return 4. 例如,如果Excel文件的日期如下:20-6-2019,它将减去今天的日期(16/6/2019)并返回4。
I've been trying to approach this with pandas and with xlrd, but each time I'm getting overwhelmed and just couldn't understand what I'm doing. 我一直试图用pandas和xlrd来解决这个问题,但每次我都不知所措,只是无法理解我在做什么。
This was my approach: 这是我的方法:
import pandas as pd
import datetime
file_name = pd.read_excel (r'C:\Users\Daniel Beilin\VSCodeProjects\ExcelReminder\test.xlsx')
df = pd.DataFrame(file_name, columns= ['Date'])
df['Date'] = pd.to_datetime(df.Date)
frmtedDate = df['Date']
today = pd.datetime.now().date()
delta = frmtedDate - today
print(delta)
You can use pd.Timestamp.today
and then extract the amount of days from the timedelta which it returns with dt.days
: 您可以使用pd.Timestamp.today
,然后从dt.days返回的timedelta中提取天dt.days
:
# Example dataframe
df = pd.DataFrame({'Date':['20-6-2019', '21-6-2019', '25-6-2019']})
df['Date'] = pd.to_datetime(df['Date'])
Date
0 2019-06-20
1 2019-06-21
2 2019-06-25
(df['Date'] - pd.Timestamp.today()).dt.days
0 3
1 4
2 8
Name: Date, dtype: int64
Note in this case 3 days for 20-6-2019
is correct, since there are 3 full days between date now and the 20th of june. 请注意,在这种情况下, 20-6-2019
3天是正确的,因为从现在到6月20日之间有3天完整。
You can set a format option in you pd.to_datetime()
function. 您可以在pd.to_datetime()
函数中设置格式选项。 In your situation this should work out: 在你的情况下,这应该成功:
df['Date'] = pd.to_datetime(df.Date, format="%d-%m-%Y)
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