将“ if”语句合并到一个比较运算符链中

Question

Please help me in making one comparison operator chain out of the code below. I am thinking in terms of

if 0 <= file >= 7 or 0 <= rank >= 7:
    file = 0
    rank = 0

Here's the code to concise:

if file <= 0:
    file = 0

if rank <= 0:
    rank = 0

if file => 7:
    file = 7

if rank => 7:
    rank = 7

Answer 1

how about

file = max(min(file, 7), 0)
rank = max(min(rank, 7), 0)

min(file, 7) will return 7 at most; max(x, 0) will return 0 or something bigger.

---

you can only use chaining to check if something is within a range:

0 <= x <= 7

you cannot use chaining to check if something is outside a range:

0 <= x >= 7

will always be False (as it evaluates as (0 <= x) and (x >= 7) ).

---

if your variables are integers you could use:

x not in range(0, 8)

Answer 2

def clip(number: int, lower_bound: int, upper_bound: int) -> int:
    clipped_lower = max(lower_bound, number)
    clipped = min(clipped_lower, upper_bound)
    return clipped

lower_bound = 0
upper_bound = 7
file = clip(file, lower_bound, upper_bound)
rank = clip(rank, lower_bound, upper_bound)

If you already happen to be using numpy , then it already has clip : https://docs.scipy.org/doc/numpy/reference/generated/numpy.clip.html

Answer 3

Thanks for all your help, but what I ended up with is this:

file = 0 if file < 0 else 7 if file > 7 else file
rank = 0 if rank < 0 else 7 if rank > 7 else rank