graphql_flutter 返回 LazyCacheMap，built_value deserializeWith JSON String，如何让它们协同工作

Question

graphql_flutter return LazyCacheMap , built_value deserializeWith JSON String , how to make them work together.

1. I use graphql_flutter to fetch data, and response give the result data as LazyCacheMap .
2. And using built_value for data model & data serialization, but since deserializeWith working with JSON String .

What's the best way to work with them together ?

• Should I just convert LazyCacheMap 's data of to String and call deserializeWith ?
• should I use other serialization pubs ?

Answer 1

First encode the response LazyCacheMap to JSON using the dart:convert package, then perform whatever operation you want.

import 'dart:convert';

GraphQLClient _client = graphQLConfiguration.clientToQuery();
QueryResult result = await _client.query(
  QueryOptions(
    documentNode: gql(GraphQlQueries.authenticateUser()),
  )
);

print(jsonEncode(result.data));

Worked for me.