使用正则表达式（python）对括号内的文本进行脱色

Question

strs = [
    "I like to run head first into a wall (not)"
    "klsjlsk klsjdkls ,m s,mdn,mnsd,m (123)"
    "a b c d e f g h i (j?)"
]

I want to remove the " (not), (123), (j?)"

why is

re.sub(r' (\([*]\))$', '', strs(0))

not doing it and what's the proper way?

Answer 1

Consider the following:

import re


strs = [
    "I like to run head first into a wall (not)",
    "klsjlsk klsjdkls ,m s,mdn,mnsd,m (123)",
    "a b c d e f g h i (j?)"
]

# space(\s)
# openbracket(\()
# anychar(.*)
# smallestpossiblematch(?)
# closebracket(\))
pattern = r'\s*\(.*?\)'

# list comprehension with new strings
new = [re.sub(pattern, '', strs[i]) for i in range(len(strs))]

Answer 2

You're using a capture group (the outside parentheses) to capture everything inside the parentheses. However, since you're not reusing that captured data, that's unnecessary. If you just want to remove all parentheses and the enclosed text at the end of a line (my guess based on what you supplied), you can do

re.sub(r'\([^\)]*\)$', '', strs[0])

Example: https://regex101.com/r/FOTTfi/1

If it's important to remove the space before the parentheses as well, just use a \\s or \\s+ at the start.

Yours doesn't work because [*] isn't doing what you think. It's looking for the literal * . If you want to find any number of characters, use .* instead.

Answer 3

这是您需要使用print re.sub(r'\\([^)]*\\)', '', strs[0])的正则表达式