[英]Python regex replace words within brackets
How to replace word within brackets with empty string for repetitive words?如何用空字符串替换括号内的单词重复单词?
import re
resource_path = '/mdm/v1/{appId}/templates/{templateId}'
clean_resource_path = re.sub(r"\s*\{[^()]*\}$", '', resource_path)
print(clean_resource_path)
I get output as /mdm/v1/
but ideally I want output as /mdm/v1/templates
.我得到输出为
/mdm/v1/
但理想情况下我希望输出为/mdm/v1/templates
。 I know the my regex is replacing everything between {}
with empty quotes, but I want only to the next available quote.我知道我的正则表达式正在用空引号替换
{}
之间的所有内容,但我只想要下一个可用的引号。
import re
resource_path = '/mdm/v1/{appId}/templates/{templateId}'
clean_resource_path = re.sub(r"/{\w*}*", '', resource_path)
print(clean_resource_path)
output输出
/mdm/v1/templates
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