[英]Plotting isolated nodes in NetworkX
import networkx as nx
import numpy as np
from scipy.sparse import coo_matrix #coordinate sparse matrices
A = np.zeros([4,4])
A[0,1] = A[1,2] = 1
S = coo_matrix(A)
edges = np.r_[[S.row], [S.col]].T
G = nx.Graph()
G.add_edges_from(edges)
nx.draw(G)
When I run that script, I get this: 当我运行该脚本时,得到以下信息:
But there are four nodes. 但是有四个节点。 How can I get the isolated fourth node to show?
如何显示孤立的第四个节点?
By only adding the edges to the graph, networkx has no way of knowing about the additional vertices; 通过仅将边线添加到图形,networkx无法知道其他顶点。 all it's doing is adding the vertices of each edge that you're providing.
它所做的就是添加要提供的每个边的顶点。 If, instead, you explicitly add all vertices, then you're good to go:
相反,如果您显式添加所有顶点,那么就可以了:
G = nx.Graph()
G.add_nodes_from(range(len(A)))
G.add_edges_from(edges)
nx.draw(G)
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