Networkx viz - 如何在以圆形布局绘制节点之前对节点进行排序？

Question

I am trying to create timetables or cardioid graph using network in python this is my code

import matplotlib.pyplot as plt
import networkx as nx
G = nx.Graph()
n = 10
for i in range(1,n):
    if i*2 < n:
        G.add_node(i, weight=i)
        G.add_node(i*2, weight=i*2)
        G.add_edge(i, i*2)
    else:
        G.add_node(i, weight=i)
        G.add_node(i*2-n, weight=i*2-n)
        G.add_edge(i,i*2 - n)
plt.figure(figsize=(10,6))
nx.draw_networkx(G, pos=nx.circular_layout(G), node_size=1000)

But then I am getting something like this enter image description here Whereas I want nodes to be in aa sorted manner like 0,1,2... in circular format, how do I achieve that?

Answer 1

You can achieve it by using

nx.draw_networkx(G, pos=nx.circular_layout(sorted(G.nodes()), node_size=1000)

to get the nodes sorted in an anticlockwise manner.
Otherwise, for a clockwise ordering you can use

nx.draw_networkx(G, pos=nx.circular_layout(sorted(G.nodes(), reverse=True)), node_size=1000)

Example: