在networkx中使用draw_circular时如何修复节点的位置？

Question

I want to draw two graphs are almost same, the only difference is that the second one will have some edges grayed out. And I want nodes in the second graph stay exactly where they are in the first graph.

Answer 1

You need to define the optional pos argument.

In your case using circular layout pos = nx.circular_layout(G) . Then you call the plotting commands like nx.draw(G, pos, other_arguments...) .