如何将Java /资源文件获取到InputStream？

Question

I have an excel file in src/main/resources (/resources/files/templates). I want to read it to InputStream. I am not finding the right syntax for this.

String fn = "/resources/files/censusTemplates/SimpleStandardTemplate.xlsm";

    try {
        InputStream inputStream = new URL("file:///"  + fn).openStream();

Above is not working. I think the path is wrong. How to give correct path for files stored in resources?

Answer 1

这对我有用。

InputStream is = YourClass.class.getClassLoader().getResourceAsStream("relative path to your file starting from resources folder");

Answer 2

If you are in any method (static or non-static):

String fn = "/resources/files/censusTemplates/SimpleStandardTemplate.xlsm";
InputStream in = Clazz.class.getResourceAsStream(fn);

Where Clazz is the name of the class you are in.

If you are in a non-static method:

String fn = "/resources/files/censusTemplates/SimpleStandardTemplate.xlsm";
InputStream in = getClass().getResourceAsStream(fn);