I have an excel file in src/main/resources (/resources/files/templates). I want to read it to InputStream. I am not finding the right syntax for this.
String fn = "/resources/files/censusTemplates/SimpleStandardTemplate.xlsm";
try {
InputStream inputStream = new URL("file:///" + fn).openStream();
Above is not working. I think the path is wrong. How to give correct path for files stored in resources?
这对我有用。
InputStream is = YourClass.class.getClassLoader().getResourceAsStream("relative path to your file starting from resources folder");
If you are in any method (static or non-static):
String fn = "/resources/files/censusTemplates/SimpleStandardTemplate.xlsm";
InputStream in = Clazz.class.getResourceAsStream(fn);
Where Clazz
is the name of the class you are in.
If you are in a non-static method:
String fn = "/resources/files/censusTemplates/SimpleStandardTemplate.xlsm";
InputStream in = getClass().getResourceAsStream(fn);
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