过滤具有多个条件的复杂数组

Question

var sd = {
"searchData": [
    {
        "description": "ISU ISU",
        "tags": {
            "portfolio": [
                "p1",
                "p2",
                "p3"
            ],
            "industry": [
                "i1",
                "i2",
                "i3"
            ]
        },

    },
    {
        "description": null,
        "tags": {
            "portfolio": [
                "p1",
                "p2",
                "p3"
            ],
            "industry": [
                "i1",
                "i4",
                "i5"
            ]
        },
        {
        "description": null,
        "tags": {
            "portfolio": [
                "p4",
                "p5",
                "p6"
            ],
            "industry": [
                "i1",
                "i2",
                "i3"
            ]
        },
    }
]

}

I will get this data from a api. I want to filter the above with portfolio value of p1 and industry with i1.

I tried using filter but not able to get the required result. I cannot use other libraries like loadash or undersore. I have to do it from nomal ES6 methods.

Answer 1

You can use the filter method. Not sure how you used it, but this is how it should look.

sd.searchData.filter(obj => {
    if (!obj.tags.industry.includes("i1"))
        return false;
    if (!obj.tags.portfolio.includes("p1"))
        return false;
    return true;
})

Or a one liner:

sd.searchData.filter(obj => obj.tags.industry.includes("i1") && obj.tags.portfolio.includes("p1"));

Answer 2

You could take an array with the search criteria and filter the array by taking the key and value for a check.

 var data = { searchData: [{ description: "ISU ISU", tags: { portfolio: ["p1", "p2", "p3"], industry: ["i1", "i2", "i3"] } }, { description: null, tags: { portfolio: ["p1", "p2", "p3"], industry: ["i1", "i4", "i5"] } }, { description: null, tags: { portfolio: ["p4", "p5", "p6"], industry: ["i1", "i2", "i3"] } }] }, search = [["portfolio", "p1"], ["industry", "i1"]], result = data.searchData.filter(({ tags }) => search.every(([k, v]) => tags[k].includes(v))); console.log(result);

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Answer 3

 let sd = { searchData : [ { "description": "ISU ISU", "tags": { "portfolio": [ "p1", "p2", "p3" ], "industry": [ "i1", "i2", "i3" ] }, }, { "description": null, "tags": { "portfolio": [ "p1", "p2", "p3" ], "industry": [ "i1", "i4", "i5" ] }, }, { "description": null, "tags": { "portfolio": [ "p4", "p5", "p6" ], "industry": [ "i1", "i2", "i3" ] }, } ] }; console.log(sd.searchData.filter((element) => { return element.tags.portfolio.includes('p1') && element.tags.industry.includes('i1') }));

Answer 4

You can do:

 const sd = {searchData : [{"description": "ISU ISU","tags": {"portfolio": ["p1","p2","p3"],"industry": ["i1","i2","i3"]},},{"description": null,"tags": {"portfolio": ["p1","p2","p3"],"industry": ["i1","i4","i5"]},},{"description": null,"tags": {"portfolio": ["p4","p5","p6"],"industry": ["i1","i2","i3"]},}]}; const result = sd.searchData.filter(({tags}) => tags.industry.includes('i1') && tags.portfolio.includes('p1')); console.log(result);