按多个条件过滤数组

Question

I'm looking to filter the following array:

const array = 
[{city: "Fullerton", techName: ["Sean"], routeName: ["Route 1"], routeDay: "Monday"},
{city: "Long Beach", techName: ["Sean", "Greg"], routeName: ["Route 1", "Route 3"], routeDay: "Monday"}, 
{city: "Huntington Beach", techName: ["Sean"], routeName: ["Route 1"], routeDay: "Monday"}];

With the following array:

const filters = [{type: "routeDay", filter: "Monday"}, {type: "techName", filter: "Greg"}];

I am filtering a table with multiple filters and I cannot figure out how to filter by both filters. I am able to filter by one or the other, but one one and the other.

Any help is appreciated, thanks!!

Answer 1

You can filter the array, and for each item use Array.every() to iterate the array of filters , and check if the values are acceptable.

Get the relevant value by type from the current object. If it's an array check if it contains the filter 's value. If not compare value and filter .

 const array = [{city: "Fullerton", techName: ["Sean"], routeName: ["Route 1"], routeDay: "Monday"}, {city: "Long Beach", techName: ["Sean", "Greg"], routeName: ["Route 1", "Route 3"], routeDay: "Monday"}, {city: "Huntington Beach", techName: ["Sean"], routeName: ["Route 1"], routeDay: "Monday"}]; const filters = [{type: "routeDay", filter: "Monday"}, {type: "techName", filter: "Greg"}]; const result = array.filter(o => filters.every(({ type, filter }) => { const value = o[type]; return Array.isArray(value) ? value.includes(filter) : value === filter; })); console.log(result);