您如何将参数传递给作为参数传递的脚本？

Question

Basically the title, I don't know how to pass an argument to a script that is being passed as an argument in a shell command. Take the command below for example:

$someexe --arg-for-someexe scriptA.py

somexe is going to read from scriptA and perform a bunch of tasks and then spit out some data into a destination file hard-coded into scriptA. How would I pass the destination file into scriptA as a command line argument? In python I know I can get arguments using sys.argv[i] but someexe will also try to grab those arguments and could cause problems. How could I accomplish this?

Answer 1

You could do something like that:

Caller script (scripta.py):

import os
def main(args):
    os.system('python scriptb.py' + ' ' + str(args))

if __name__ == '__main__':
    import sys
    args = sys.argv[1:]
    main(args)

Receiver script (scriptb.py):

if __name__ == '__main__':
    import sys
    args = sys.argv[1:]
    print(args)

To call script a - say in a terminal:

python scripta.py arg1 42 arg2 43

Will print in scriptb.py terminal:

['[arg1,', '42,', 'arg2,', '43]']

os.system() spawns it in a separate shell/process. May or not be what you want.