如何在字典中使用空格分隔的输入，并将每个新输入与新键值存储在一起？

Question

How to create a dictionary from a string composed by space separated words with i for i in range(0, n) as key in the dictionary ?

Tried this:

i = 0
map(dic[i+=1],input().split())

It didn't work.

It should output this:

dic={0:'apple',1:'grapes',2:'orange',3:'banana'}

Answer 1

input_str = "Hello world"
result = {key: value for key, value in enumerate(input_str.split())}
print(result)

Output:

{0: 'Hello', 1: 'world'}

But you can use a list since this data structure is made for iterating over their contents and keeps order. If you want an int as key, just use enumerate(your_list) .

In Python, when to use a Dictionary, List or Set?

Answer 2

You could use enumerate :

d = {}
for i, v in enumerate(input().split()):
    d[i] = v

Or simply:

d = dict(enumerate(input().split()))

---

But why do that? use a list ...

Since your keys are simply (ordered!) integers, using a dict seems an overkill as to access integer-indexed values from a list is also O(1) . For example, let's look at a small comparison with the 2 versions:

l = input().split()
d = dict(enumerate(l))

We have:

>>> print(l)
['apple', 'orange', 'banana']
>>> print(d)
{0: 'apple', 1: 'orange', 2: 'banana'}

Now let's see how we will grab values:

>>> l[0]
'apple'
>>> d[0]
'apple'
>>> l[2]
'banana'
>>> d[2]
'banana'

Dictionaries have a small memory overhead and so for this case using a dictionary doesn't give any advantage.

Answer 3

input_ = input("enter your fruits:").split(' ')

print (dict(zip([*range(len(input_))], input_)))
# print (dict(enumerate(input_)))

output:

enter your fruits:banana kiwi orange apple
{0: 'banana', 1: 'kiwi', 2: 'orange', 3: 'apple'}