如何将每个新输入放入python中的新列表中？

Question

I want it to be so that once the user input's their inputs, they both will go into a new list.

num = int(input("Choose a number"))

for i in range(num):
    input1, input2 = input("").split()

For each input1 and input2, I want it go into an entirely new list. For example: If I input num as 3, I would have to input, input1 and input 2, three times. I want three different lists then for that case containing just input 1 and input2.

Input: 
>> Choose a number 3
>> 4 5
>> 3 6
>> 2 2

Output: 
>> [4,5] 
>> [3,6]
>> [2,2]

Just to clarify, the "choose a number" input is entirely based on input. This means that "x" number of lists should be created with input1 and input2 based on the choose a number input (x)

Answer 1

• you can use list of lists to store the results:

num = int(input("Choose a number"))
res = [] # this will store all user inputs.
for i in range(num):
    input1, input2 = input("").split()
    res.append([input1, input2])

print(*res, sep='\n')

output

Choose a number 3
 5 2
 4 2
 6 56
['5', '2']
['4', '2']
['6', '56']

• solution 2:

num = int(input("Choose a number"))
res = dict() # this will store all user inputs.
for i in range(num):
    res['user'+str(i)] = input("").split()
print(res['user1'])

• output:

Choose a number 3
 2 5
 2 5
 36 663
['2', '5']

Answer 2

You can do it that way, for example:

num = int(input("Choose a number"))

temp = []
for _ in range(num):
    input1, input2 = input().split()
    temp.append([input1, input2])
    print(temp); temp = []

Answer 3

You need to have a main list, then add your sublist (splitted input) into it :

num = int(input("Choose a number"))
values = []
for _ in range(num):
    values.append(input("").split())

print(values) # [[4,5], [3,6], [2,2]]
print(values[1]) # [3,6]

Using a list-comprehesion, the same is

values = [input("").split() for _ in range(num)]

Do the following, to get each sublist on a new line

print(*values, sep='\n')