我如何在某个时间戳记时间运行python函数。 没有外部软件？

Question

I want to tell a python script to run a certain function when a certain timestamp time happens

I have already looked for running time specific functions but i could not find anything that answered this specific question about counting time stamps

#input is number of days till due date
dueDate = int(input('Days until it is due: '))

#86400 seconds in a day
days = dueDate * 86400

#gets current time stamp time 
currentT = int(time.time())

#gets the timestamp for due date 
alarm = days+currentT

the aim is to find the python function which can run another function from within the script at when a specified future time stamp occurs

Answer 1

Build into python is the sched module. Here is a pretty good write-up on it, and here is the official documentation. With scheduler.enter you can schedule with a delay, and with scheduler.enterabs you can schedule for a specific time.

import sched
import time

scheduler = sched.scheduler(time.time, time.sleep)

def print_event(name):
    print('EVENT:', time.time(), name)

now = time.time()
print('START:', now)

scheduler.enterabs(now+2, 2, print_event, ('first',))
scheduler.enterabs(now+5, 1, print_event, ('second',))

scheduler.run()

Outputs:

START: 1287924871.34
EVENT: 1287924873.34 first
EVENT: 1287924874.34 second

Answer 2

You could just sleep the script for that long.

time.sleep(alarm)

Source: python docs

Answer 3

Schedule is a good python module for doing this.

Usage: (From Documentation)

Install

$ pip install schedule

Usage

import schedule
import time

def job():
    print("I'm working...")

schedule.every(10).minutes.do(job)
schedule.every().hour.do(job)
schedule.every().day.at("10:30").do(job)
schedule.every(5).to(10).minutes.do(job)
schedule.every().monday.do(job)
schedule.every().wednesday.at("13:15").do(job)
schedule.every().minute.at(":17").do(job)

while True:
    schedule.run_pending()
    time.sleep(1)