从字符串中删除除智能引号之外的所有非 ASCII 字符

Question

I have this regex that removes all non-ascii characters from a string including all smart quotes:

str.replace(/[\u{0080}-\u{FFFF}]/gu,"");

But I need to keep the Smart quotes

The regex for removing Smart single quotes is: [\‘\’\‚\‛\′\‵] and for Smart double quotes is: [\“\”\„\‟\″\‶] .

I need a combined regex that that removes all non-ASCII ( [\\u{0080}-\\u{FFFF}] ) except smart quotes ( [\‘\’\‚\‛\′\‵] or [\“\”\„\‟\″\‶] ).

Answer 1

Note that you need to use the \\u{XXXX} notation in the regex with u modifier, and to build the regex you need you need to put the character class with exceptions into a negative lookahead placed right before your more generic pattern:

/(?![\u{2018}\u{2019}\u{201A}\u{201B}\u{2032}\u{2035}\u{201C}\u{201D}\u{201E}\u{201F}\u{2033}\u{2036}])[\u{0080}-\u{FFFF}]/gu

See the regex demo

Note that some chars in the Unicode table go one after another, so we may shorten the pattern using ranges:

/(?![\u{2018}-\u{201F}\u{2032}\u{2033}\u{2035}\u{2036}])[\u{0080}-\u{FFFF}]/gu

See this demo .

Answer 2

Instead of matching the non-ascii, match the ascii + the characters you need, and negate the expression. Example:

str.replace(/[^\x00-\x7F\u2018\u2019\u201A\u201B\u2032\u2035\u201C\u201D\u201E\u201F\u2033\u2036]/gu,"");