正则表达式，用于在单词之后和特殊字符之前提取文本，并排除所有其他数字

Question

I'm trying to write a regex which for a given example text

Section 2.1. 1.1.14. Minimum Rent Schedule (subiect to adjustment, if applicable):less than or greater than twelve (12) full calendar months (and such proration or adjustment being based upon the actual number of days in such Lease Year)

Output desired

Minimum Rent Schedule (subiect to adjustment, if applicable)

Everything between the word 'Section' and upuntill special character ':' . But like in here, I don't want it to capture anything with numbers.

What I have tried until now is

[Section]+.*[:]

Answer 1

This is one pattern.

Ex:

import re

s = "Section 2.1. 1.1.14. Minimum Rent Schedule (subiect to adjustment, if applicable):less than or greater than twelve (12) full calendar months (and such proration or adjustment being based upon the actual number of days in such Lease Year)"
print(re.match(r"Section[\d.\s]+(.*?):", s).group(1))

Output:

Minimum Rent Schedule (subiect to adjustment, if applicable)

---

If you have multiple elements use re.findall

Ex:

print(re.findall(r"Section[\d.\s]+(.*?):", your_text))

Answer 2

The pattern you tried uses a character class which will match any of the listed characters 1+ times.

To not match anything which contains numbers after Section , you could repeat 0+ times matching a space followed by non whitespace characters that contain at least a single number.

Capture what follows that does not contain a number in a group.

Section (?:[^\s\d]*\d\S* )*([^:]+):

Explanation

• Section Match Section and space
• (?: Non capturing group
  • [^\\s\\d]* Match any char except a whitespace char and a digit 0+ times using a negated character class
  • \\d\\S* Then match a digit followed by matching 0+ times a non whitespace char
• )* Close group and repeat 0+ times
• ([^:]+): Capture in group 1 matching 1+ times any char except a : , then match a :

Regex demo

For example

import re

regex = r"Section (?:[^\s\d]*\d\S* )*([^:]+):"
s = "Section 2.1. 1.1.14. Minimum Rent Schedule (subiect to adjustment, if applicable):less than or greater than twelve (12) full calendar months (and such proration or adjustment being based upon the actual number of days in such Lease Year)"
print(re.match(regex, s).group(1))

Result

Minimum Rent Schedule (subiect to adjustment, if applicable)

To find multiple, you could use re.findall:

print(re.findall(regex, s))

Demo using re.findall