将字典转换为元组排序列表

Question

So I am trying to convert a dictionary into a sorted list containing tuples. I have been able to convert the dictionary to a sorted list no problem. My issue is creating a tuple out of the key AND corresponding values, then passing that into a sorted list.

I have tried just turning the dictionary into a sorted list (which technically works but the tuple seems to be a separate entity in the list).

Then I tried to pull the key and the all the values apart and stitch them back together with a for statement but I've spent enough time on this now that I'm just blocked up and can't see why it won't pass through.

Below are the two functions I have tried to create:

#function #1
def sort_contacts(diction):    
    my_key_list = list(diction.keys())
    my_val_list = list(diction.values())
    for x in range(0,len(my_key_list)):
        for k in my_key_list:
            for x,v in my_val_list:
                new_val=(k, x, v)
            new_list=[new_val]
    return(new_list)

#function #2
def sort_contacts(diction):
    sorta = [(k,v) for k,v in diction.items()]
    sorta = list(sorta)
    sorta.sorta
    #sortc = sortb.split()
    return sorta

For function #1, Test Failed.
Expected:

[('Freud, Anna', '1-541-754-3010', 'anna@psychoanalysis.com'), ('Horney, Karen', '1-541-656-3010', 'karen@psychoanalysis.com'), ('Welles, Orson', '1-312-720-8888', 'orson@notlive.com')] 

but got:

[('Freud, Anna', '1-541-754-3010', 'anna@psychoanalysis.com')]

For function #2, Test Failed.
Expected:

[('Freud, Anna', '1-541-754-3010', 'anna@psychoanalysis.com'), ('Horney, Karen', '1-541-656-3010', 'karen@psychoanalysis.com'), ('Welles, Orson', '1-312-720-8888', 'orson@notlive.com')] 

but got:

[('Freud, Anna', ('1-541-754-3010', 'anna@psychoanalysis.com')), ('Horney, Karen', ('1-541-656-3010', 'karen@psychoanalysis.com')), ('Welles, Orson', ('1-312-720-8888', 'orson@notlive.com'))]

Answer 1

I think what you are looking for is something like:

def sort_contacts(diction):
    sorta = [(k, v[0], v[1]) for k,v in diction.items()]
    # sort it somehow? 
    return sorta

Answer 2

@Akaisteph7 thank you that answer worked. I sorted it by sorta.sort() and then everything passed through correctly.

here is the final code:

def sort_contacts(diction):
    sorta = [(k, v[0], v[1]) for k,v in diction.items()]
    sorta.sort() 
    return sorta

Thanks everybody!