在 Python 中将元组列表转换为字典列表

Question

I am trying to convert a list of tuple to a list of dictionary with a data that looks like this:

data =[
    ('base-certificate', 60, 3, 2022), 
    ('case-certificate', 1, 3, 2022), 
    ('standard-certificate', 7, 3, 2022),
    ('base-certificate', 50, 4, 2022), 
    ('case-certificate', 80, 4, 2022), 
    ('standard-certificate', 10, 4, 2022)
]

The last two numbers are dates representing month and year, this means that there can also be data for April(4), May(5), etc. and it would be unique. so to create a date object in javascript these two numbers are needed preferably in a list [3, 2022].

I would like an output that looks like this:

[
    {x:[3, 2022], base: 60, case:1, standard: 7}, 
    {x:[4, 2022], base: 50, case:80, standard: 10} 
]

I tried using the defaultdict from the collection library:

from collections import defaultdict
data=defaultdict(dict) 

for a, b, c, d in se:
    if "x" not in data[c, d]:
        data[c, d]['x'] = [c,d]
    data[c, d][a] = b
        
print(data)  

The result of the code was:

defaultdict(<class 'dict'>, {(3, 2022): {'x': [3, 2022], 'base-certificate': 60, 'case-certificate': 1, 'standard-certificate': 7}, (4, 2022): {'x': [4, 2022], 'base-certificate': 50, 'case-certificate': 80, 'standard-certificate': 10}})

it was close but am missing something. Please what is the best approach in this case? and what am I am doing wrong, Thank you for your kind response.

Answer 1

Here's a possible solution using itertools.groupby . If the dates are sorted you can use groupby directly on the data, if not, you should sort by date first.

from itertools import groupby

result = []
for key, group in groupby(data, lambda x: (x[2], x[3])):
    r = {'x': key}
    for a, b, _, _ in group:
        r[a.partition('-')[0]] = b
    result.append(r)

print(result)

Output:

[{'x': (3, 2022), 'base': 60, 'case': 1, 'standard': 7}, {'x': (4, 2022), 'base': 50, 'case': 80, 'standard': 10}]

Answer 2

Try:

data = [
    ("base-certificate", 60, 3, 2022),
    ("case-certificate", 1, 3, 2022),
    ("standard-certificate", 7, 3, 2022),
    ("base-certificate", 50, 4, 2022),
    ("case-certificate", 80, 4, 2022),
    ("standard-certificate", 10, 4, 2022),
]

out = {}
for name, val, month, year in data:
    out.setdefault((month, year), {}).update(
        {"x": [month, year], name.split("-")[0]: val}
    )

print(list(out.values()))

Prints:

[
    {"x": [3, 2022], "base": 60, "case": 1, "standard": 7},
    {"x": [4, 2022], "base": 50, "case": 80, "standard": 10},
]