如何检查数组是否包含值，这是对象的属性？

Question

I have an object like this:

    obj: {
          "abc": "xxxxx",
          "def": "yyyyy",
          "ghi": "zzzzz"
         }

and an array like this (only 1 value):

    array: ["def"]

result should be:

    array: ["yyyyy"]

Im not sure what to try, thats why i didn't. I hope you can help me with that

Answer 1

If the array really only has one entry, you can easily use that entry get the value of the property it names using brackets notation :

value = obj[array[0]];

To build a new array with just that value, you can use an array literal:

[value]

So all together:

array = [obj[array[0]]];

Live example:

 const obj = { "abc": "xxxxx", "def": "yyyyy", "ghi": "zzzzz" }; let array = ["def"]; array = [obj[array[0]]]; console.log(array); 

Answer 2

You can use map method to do it...

Code is:

obj = {
   "abc": "xxxxx",
   "def": "yyyyy",
   "ghi": "zzzzz"
}

array = ["def", "abc"];

array = array.map(elem => {
    if(obj[elem]){
        return obj[elem];
    }
})

now array will be ["yyyyy", "xxxxx"]