在 JavaScript 中检查数组是否包含具有特定属性值的对象？

Question

If I have something like

[Object(id:03235252, name:"streetAddress"), Object(id:32624666, name:"zipCode")...]

How can I remove an object from that array that has name set to "zipCode"?

Answer 1

If you need to modify the existing Array, you should use splice() .

for (var i = array.length - 1; i > -1; i--) {
    if (array[i].name === "zipCode")
        array.splice(i, 1);
}

Notice that I'm looping in reverse. This is in order to deal with the fact that when you do a .splice(i, 1) , the array will be reindexed.

If we did a forward loop, we would also need to adjust i whenever we do a .splice() in order to avoid skipping an index.

Answer 2

arr = arr.filter(function (item) {
  return (item.name !== 'zipCode');
});

Answer 3

var i = array.length;
while(i-- > 0) {
    if (array[i].name === "zipCode")
        array.splice(i, 1);
}

• Loop through the array backwards (so you won't have to skip indexes when splicing)
• Check each item's name if it's "zipCode"
  • If it is, splice it off using yourArray.splice(index,1) ;

Then either:

• continue if there is a possibility of having more than one name having the value "zipCode"
• break the loop

Answer 4

Updated suggestion

Updated this answer due to doing prototypes on arrays are bad prac so to get people who use the suggestion to write better code here is a better option:

const myArr = [
  {
    name: "lars",
    age: 25
  }, {
    name: "hugo",
    age: 28
  }, {
    name: "bent",
    age: 24
  }, {
    name: "jimmy",
    age: 22
  }
];

const findAndRemove = (array, prop, value) => {
  return array.filter((item) => item[prop] !== value);
}

const newArr = findAndRemove(myArr, 'name', 'jimmy')

console.log(newArr)

New code can be found and tested here

Old suggestion

This can also be done with a prototype on the array

 
 
 
  
  
  Array.prototype.containsByProp = function(propName, value){ for (var i = this.length - 1; i > -1; i--) { var propObj = this[i]; if(propObj[propName] === value) { return true; } } return false; } var myArr = [ { name: "lars", age: 25 }, { name: "hugo", age: 28 }, { name: "bent", age: 24 }, { name: "jimmy", age: 22 } ]; console.log(myArr.containsByProp("name", "brent")); // Returns false console.log(myArr.containsByProp("name", "bent")); // Returns true
 
 
 

Code can also be found and tested here

Answer 5

This may be a detailed and easy solution.

//plain array
var arr = ['a', 'b', 'c'];
var check = arr.includes('a');
console.log(check); //returns true
if (check)
{
   // value exists in array
   //write some codes
}

// array with objects
var arr = [
      {x:'a', y:'b'},
      {x:'p', y:'q'}
  ];

// if you want to check if x:'p' exists in arr
var check = arr.filter(function (elm){
    if (elm.x == 'p')
    {
       return elm; // returns length = 1 (object exists in array)
    }
});

// or y:'q' exists in arr
var check = arr.filter(function (elm){
    if (elm.y == 'q')
    {
       return elm; // returns length = 1 (object exists in array)
    }
});

// if you want to check, if the entire object {x:'p', y:'q'} exists in arr
var check = arr.filter(function (elm){
    if (elm.x == 'p' && elm.y == 'q')
    {
       return elm; // returns length = 1 (object exists in array)
    }
});

// in all cases
console.log(check.length); // returns 1

if (check.length > 0)
{
   // returns true
   // object exists in array
   //write some codes
}