如何应用两个'如果; 在 python 中定义

Question

input=('befelled','recalled','expelled','swelled','tested','marked','scott','brutt')

I want an output which looks like,

output=('befel','recal','expel','swel','test','mark','scott','brutt')

It's like if the word ends with 'ed', remove the 'ed' else return to the similar word, the second condition would be if the word ends with 'll' after applying the first condition then remove the 'l' and return the output

I want to apply two ifs

First if will check for all the words which end with 'ed' and then this if will remove the last two alphabets from the words which satisfy the first if.

Then I want to aplly the second if which will look for all the word s which end with 'll'

words=('befelled','recalled','expelled','swelled','tested','marked','scott','brutt') . 
def firstif(words):  
    for w in words:  
        if w.endswith('ed'):  
             return (w[:-2]) . 
        else:  
            return(w) . 
firstif(w) . 
words2=tuple(firstif(w)) . 
def secondif(words2):  
    for w2 in words2:  
        if w2.endswith('ll'):  
            return (w2[:-1]) . 
        else:  
            return(w2) . 
secondif(w2)

This code is running but giving me weird output

Answer 1

Using nested loops to check would be a better idea. Just try:

words=('befelled','recalled','expelled','swelled','tested','marked','scott','brutt') . 
def fix_word(words):
    temp = []
    for w in words:
        if w.endswith('ed'):
            if w.endswith('lled'):
                temp.append(w[:-3])
            else:
                temp.append(w[:-2])
        else:
            temp.append(w)
    return tuple(temp)

Answer 2

I can also use elif

words=('befelled','recalled','expelled','swelled','tested','marked','scott','brutt')
a=[]
for w in words:
    if w.endswith("lled"):
        a.append(w[:-3])    
    elif w.endswith("ed"):
        a.append(w[:-2])
    else:
        a.append(w)

result

>>>tuple(a)
('befel', 'recal', 'expel', 'swel', 'test', 'mark', 'scott', 'brutt')

Answer 3

The alternative way by using map()

Note: I don't recommend you to use input as a variable name since there's a function called input() as well.

def check(word):
    temp_word = word[:-2] if word.endswith('ed') else word
    return temp_word[:-1] if temp_word.endswith('ll') else temp_word

user_input=('befelled','recalled','expelled','swelled','tested','marked','scott','brutt')

res = tuple(map(check, user_input))

Result:

res
('befel', 'recal', 'expel', 'swel', 'test', 'mark', 'scott', 'brutt')

Answer 4

You could solve it in pythonic way (one line)

words = ['befelled','recalled','expelled','swelled','tested','marked','scott','brutt']
clean_words = [(e[:-3] if e.endswith('lled') else e[:-2] if e.endswith('ed') else e ) for e in words ]

Answer 5

You can also use slicing.    
inputs=('befelled','recalled','expelled','swelled','tested','marked','scott','brutt')

    def clean_word(words):
      result = []
      for word in words:
        if word[-4:] == 'lled':
          result.append(word[:-3])
        elif word[-2:] == 'ed':
          result.append(word[:-2])
        else:
          result.append(word)
      return result

    print(clean_word(inputs))