如何在python中比较“ hello：” ==“ hello”

Question

我想忽略字符串中的符号，并与非符号字符串name="Avengers Endgame"

find_element_by_link_text(name.title()).click()

<a href="#">Avengers: Endgame</a>

Answer 1

You could use a regex on the word class ( \\W ). From the link,

 \\W Matches any character which is not a word character. This is the opposite of \\w. If the ASCII flag is used this becomes the equivalent of [^a-zA-Z0-9_]. If the LOCALE flag is used, matches characters considered alphanumeric in the current locale and the underscore. 

Like,

import re
a = 'Avengers Endgame'
b = 'Avengers: Endgame'
if re.sub(r'[\W]', '', a) == re.sub(r'[\W]', '', b):
    print("They match")

Answer 2

I wrote this function for another project. Use re module, I guess it can help you.

def convert_string(str):
    '''
    return the string without any signs

    ex :
    input = 'abcdefghijklmnopqrstuvwxyz123456789!@#$%^&*()-=_+'
    ouput = 'abcdefghijklmnopqrstuvwxyz123456789'
    '''

    pat = re.compile(r'[^a-zA-Z0-9]', flags=re.IGNORECASE)
    return pat.sub('', str)

Answer 3

you could use a generator expression to only yield characters from your string that are alphanumeric or whitespace, then join them back into a new string:

text = 'Avengers: Endgame'
stripped_text = ''.join(char for char in text if char.isalnum() or char.isspace())

your new string would then be: Avengers Endgame