在Python中使用zip映射2D数组的列表

Question

I have the following labels and values and trying to get the Output below using the code:

lables: ['a','b','c']

values: array([[ 7963.92759169, -2931.3518914 ,  3360.79428745],
               [ 7964.28495515, -2930.99452794,  3361.15165092],
               [ 7965.60367246, -2929.67581063,  3362.47036823]])

for label, score in zip(lables,values):
   print("{}:{}".format(label,score)

Expected Output:

  a: 7963.92759169
  b: -2930.99452794
  c: 3362.47036823

But I don't get the expected output. Could anyone help on what is going wrong with the zip function?

Answer 1

Try the below code. Hope this would help. Normally Zip function will give this ouput.

lables= ['a','b','c']

values= [[ 7963.92759169, -2931.3518914 ,  3360.79428745],
               [ 7964.28495515, -2930.99452794,  3361.15165092],
               [ 7965.60367246, -2929.67581063,  3362.47036823]]

for label, score in zip(lables,values):
    print("{}:{}".format(label,score[0]))

Output will be:

a:7963.92759169
b:7964.28495515
c:7965.60367246

But if you want diagonal elements then you have use a counter or you can use enumerate.

for index, (label, score) in enumerate(zip(lables,values)):
    print(score[index])
    print("{}:{}".format(label,score[index]))

Ouput will be :

a:7963.92759169
b:-2930.99452794
c:3362.47036823

Answer 2

Using enumerate

Ex:

import numpy as np

lables = ['a','b','c']
values = np.array([[ 7963.92759169, -2931.3518914 ,  3360.79428745],
               [ 7964.28495515, -2930.99452794,  3361.15165092],
               [ 7965.60367246, -2929.67581063,  3362.47036823]])

for idx, (label, score) in enumerate(zip(lables,values)):
   print("{}:{}".format(label,score[idx]))

Output:

a:7963.92759169
b:-2930.99452794
c:3362.47036823