在python中打印一个非常大的整数

Question

I am trying to print a very large number by calculating very large powers of an integer. Although my code is correct, i am not observing the desired output.

Generally, python interpreter can print very large integer as much as the system memory supports. With that assumption in mind below is the code i am running.

a = int(input())
b = int(input())
c = int(input())
d = int(input())

import math
if a in range(1,1001):
    if b in range(1,1001):
        if c in range(1,1001):
            if d in range(1,1001):
                print((math.pow(a,b)+math.pow(c,d)))

The output which i am observing is

4710194409608608302099333120

The output which is expected is

4710194409608608369201743232

Can you please provide me pointers to how this can be solved? Input Values are:

a = 9
b = 29
c = 7
d = 27

Answer 1

You are running into the limits of floating point precision. From the documentation:

Unlike the built-in ** operator, math.pow() converts both its arguments to type float. Use ** or the built-in pow() function for computing exact integer powers.

So just use **

>> 9**29+7**27
4710194409608608369201743232

Answer 2

math.pow converts the inputs to float

The expected result you are showing is the result you get when you do:

x = 9**29
y = 7**27
print(x+y)

The result you are seeing comes from this:

x = float(9**29)
y = float(7**27)
print(int(x+y))

Answer 3

try it like this

>>> 9 ** 29 + 7 ** 27
4710194409608608369201743232