Javascript最大最小平均

Question

I'm looking for the Max, Min, Avg to this code with an expected output of [10,-2,3.5]

function MaxMinAvg (arr){

    var max = arr[0]
    var min = arr[0]
    var sum = arr[0]

    for (var i = 1; i < arr.length; i++){

    if (arr[i] > max){
    max = arr[i]
    }
    if (arr[i] < min){
    min = arr[i];
    }
    sum = sum + arr[i];
    var avg = arr[i] / arr.length;
    var arr2 = [max, min, avg];
    }
    return arr2;
    }

[10,-2,3.5]

Answer 1

Your code is almost correct, but you need to move avg calculation and final array creation outside the for loop. Also, the average would be the sum divided by total units.

 const maxMinAvg = arr => { let max = arr[0]; let min = arr[0]; let sum = arr[0]; for (var i = 1; i < arr.length; i++){ if (arr[i] > max){ max = arr[i] } if (arr[i] < min){ min = arr[i]; } sum = sum + arr[i]; } return [max, min, sum / arr.length];; }; console.log(maxMinAvg([1, 5, 10, -2])); 

A slightly more succinct version using array::reduce:

 const maxMinAvg = arr => { const [max, min, sum] = arr.reduce(([max, min, sum], current) => { if (max < current) max = current; if (min > current) min = current; sum += current; return [max, min, sum]; }, [arr[0], arr[0], arr[0]]); return [max, min, sum / arr.length];; }; console.log(maxMinAvg([1, 5, 10, -2]));