Javascript最大最小平均

Question

我正在尋找此代碼的最大，最小，平均，其預期輸出為[10,-2,3.5]

function MaxMinAvg (arr){

    var max = arr[0]
    var min = arr[0]
    var sum = arr[0]

    for (var i = 1; i < arr.length; i++){

    if (arr[i] > max){
    max = arr[i]
    }
    if (arr[i] < min){
    min = arr[i];
    }
    sum = sum + arr[i];
    var avg = arr[i] / arr.length;
    var arr2 = [max, min, avg];
    }
    return arr2;
    }

[10,-2,3.5]

Answer 1

您的代碼幾乎是正確的，但是您需要將avg計算和最終數組創建移到for循環之外 。 同樣，平均值將是總和除以總單位。

 const maxMinAvg = arr => { let max = arr[0]; let min = arr[0]; let sum = arr[0]; for (var i = 1; i < arr.length; i++){ if (arr[i] > max){ max = arr[i] } if (arr[i] < min){ min = arr[i]; } sum = sum + arr[i]; } return [max, min, sum / arr.length];; }; console.log(maxMinAvg([1, 5, 10, -2])); 

使用數組稍微更簡潔的版本::減少：

 const maxMinAvg = arr => { const [max, min, sum] = arr.reduce(([max, min, sum], current) => { if (max < current) max = current; if (min > current) min = current; sum += current; return [max, min, sum]; }, [arr[0], arr[0], arr[0]]); return [max, min, sum / arr.length];; }; console.log(maxMinAvg([1, 5, 10, -2]));