[英]How to remove '_' from the output in python code?
I have written one python code in which final output is coming with '_' symbol. 我写了一个python代码,最终输出中带有'_'符号。 So i want to remove this symbol.
所以我想删除这个符号。
import re
from itertools import groupby
file = ["meta_data_02154.csv", "meta_data_021694.csv", "meta_data_loop_02365.csv", "meta_data_loops_0256365.csv", "output.csv"]
f = [list(i) for j, i in groupby(file, lambda a : re.split(r'\d*.csv$', a)[0])]
print(f)
for pattern in f:
#print(pattern)
print((re.split(r'\d*.csv$', pattern[0]))[0])
Output: 输出:
[['meta_data_02154.csv', 'meta_data_021694.csv'], ['meta_data_loop_02365.csv'], ['meta_data_loops_0256365.csv'], ['output.csv']]
meta_data_
meta_data_loop_
meta_data_loops_
output
Desire Output: 需求输出:
[['meta_data_02154.csv', 'meta_data_021694.csv'], ['meta_data_loop_02365.csv'], ['meta_data_loops_0256365.csv'], ['output.csv']]
meta_data
meta_data_loop
meta_data_loops
output
import re
from itertools import groupby
file = ["meta_data_02154.csv", "meta_data_021694.csv", "meta_data_loop_02365.csv", "meta_data_loops_0256365.csv", "output.csv"]
f = [list(i) for j, i in groupby(file, lambda a : re.split(r'\d*.csv$', a)[0])]
print(f)
for pattern in f:
#print(pattern)
print((re.split(r'\d*.csv$', pattern[0]))[0].rstrip('_'))
Use rstrip()
使用
rstrip()
val = "sad_"
print(val.rstrip('_'))
Output: sad
Description
描述
rstip()
Returns a copy of the string with right trailing characters removed.rstip()
返回字符串的副本,其中删除了右尾字符。
Alternatively print(val[:-1])
will give same result in this case. 另外,在这种情况下,
print(val[:-1])
将得到相同的结果。
Try pattern r'_?\\d*.csv$'
. 尝试使用模式
r'_?\\d*.csv$'
。
Ex: 例如:
import re
from itertools import groupby
file = ["meta_data_02154.csv", "meta_data_021694.csv", "meta_data_loop_02365.csv", "meta_data_loops_0256365.csv", "output.csv"]
f = [list(i) for j, i in groupby(file, lambda a : re.split(r'\d*.csv$', a)[0])]
print(f)
for pattern in f:
#print(pattern)
print((re.split(r'_?\d*.csv$', pattern[0]))[0])
You may use print((re.split(r'\\d*.csv$', pattern[0]))[0].rstrip('_')
but you might as well use a better regex and .search
instead of split
. 您可以使用
print((re.split(r'\\d*.csv$', pattern[0]))[0].rstrip('_')
但也可以使用更好的正则表达式和.search
代替split
。
I'm not sure what you used groupby
for. 我不确定您使用
groupby
的目的。
import re
file = ["meta_data_02154.csv", "meta_data_021694.csv", "meta_data_loop_02365.csv", "meta_data_loops_0256365.csv", "output.csv"]
for pattern in file:
print(re.search(r'(.+)\d*.csv$', pattern).group(1))
Outputs 输出
meta_data_02154
meta_data_021694
meta_data_loop_02365
meta_data_loops_0256365
output
You could use a one-liner, just splitting the filenames: 您可以使用单线,仅拆分文件名:
file = ["meta_data_02154.csv", "meta_data_021694.csv", "meta_data_loop_02365.csv", "meta_data_loops_0256365.csv", "output.csv"]
filePatterns = set([f.rsplit('_', 1)[0].rsplit('.csv')[0] for f in file])
print(filePatterns)
Prints: 打印:
{'meta_data_loops', 'meta_data', 'meta_data_loop', 'output'}
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