每次按不同对数将列表中的元素分组在一起

Question

I have the following question to ask. I have a list of bs4.element.Tags like [[tag1, tag2, tag3], [tag4, tag5], [tag6], [tag7, tag8, tag9, tag10]]. So each sub list contains names of actors from different movies. So the first sub-list has three actors, the second two actors and so on.

What I do is to remove the bs4.element.Tag by calling the function .text per element of each sub-list. Then I append the result to a new list which is like: [str1, str2, str3, str4, str5, str6, str7, str8, str9, str10]. Although this is not my desirable result. I want the actors in the new list to be grouped as in the original list.

So the desirable result should be: [[str1, str2, str3], [str4, str5], [str6], [str7, str8, str9, str10]] Where str = string name of each actor.

Do you know how can I achieve this?

My example (follow the pictures):

list of bs4.element.tags

list of actor names

Answer 1

It's tough to do completely without seeing your code, but you're going to want to iterate through your element tags, pull out the content from each element into a list, then append that into a final list. So something like:

final_list = []
for tag in tags_list:
    actors = tag.find_all('a')
    actors_list = [ x.text.strip() for x in actors ]
    final_list.append(actors_list)

Answer 2

You can do list comprehension as suggested by @Ezer K. But I personally prefer the map function.

actor_list = []
for tags in tag_list:
    actor_list.append(list(map(lambda x: x.text, tags)))