如何使用随机数作为 if 语句的输入？

Question

I am making a small text based adventure game, I am trying to use the random feature built into python to generate a number. Based on the number it will allow you to continue or to die on the adventure.

N/A

import random
i = random.randint(1, 2)
if i == '1':
  print("hello")
if i == '2':
  print("Hi")

N/A

Answer 1

Your code works fine. Just remove the quotes:

import random
i = random.randint(1, 2)
if i == 1:
  print("hello")
if i == 2:
  print("Hi")

If you have quotes around the 1 and 2, i will be evaluated as a string but you've defined it as an integer.