在Python 3中如何在if语句中使用随机函数？

Question

Here is my code for a simple coin toss program, I am new to python.

I am not getting any Errors, but the program will not print my "if" statements, it skips straight from input too input.

I am sure there is more intuitve ways to generate a coin toss program, this was just the idea I had.

Any thoughts?

import random
print('--HEADS or TAILS--')
print('Welcome Players!')
print('[H=_Heads][T=_Tails]')
print('Please ENTER {H_or_T}')

input("Heads or Tails:")
rand = (random.randint(1,2))

if rand=='1':
    print("Heads Wins!")
elif rand=='2':
    print("Tails Wins!")

input("Press ENTER to Exit")

Here is a screenshot of my code.

Answer 1

random.randint(1,2) returns the value of integer type. random.randint(a,b) document clearly says that it:

Returns a random integer N such that a <= N <= b.

But in your if you are comparing it against the value of string type, and hence your conditional statements are failing.

You need to modify your conditional statements as:

#          v no quotes here
if rand == 1:
    print("Heads Wins!")
#            v no quotes here
elif rand == 2 :   # Better to simply use `else` 
    print("Tails Wins!")

Answer 2

Like the name randint already suggests, random.randint(1,2) returns an integer between 1 and 2 (both inclusive).

If you perform 1 == '1' you compare an int with a str , which is always False . You should compare with 1 instead of '1 '.

You can also drop the elif , and use else , since we know that it will be 2 if it is not 1 , so:

input("Heads or Tails:")
rand = random.randint(1,2)  # no brackets necessary

if rand == :  # use an integer, instead of a string:
    print("Heads Wins!")
:  # else instead of elif
    print("Tails Wins!")