如何将字符分配给指针？

Question

I'm making a radix converter and I wanted to use linked list to do this because I'm new to data structures. When I assign my character to the pointer the compiler give a "error: assignment to expression with array type" error.

struct node
{

  char bin_num[25];

  struct node *next;
};

char conversion[50] = "0123456789abcdefghijklmnopqrstuvwxyz!@#$/^&*";
typedef struct node NODE;


NODE *head = NULL;

int insert (int num){

  NODE *temp;

  temp = (NODE *) malloc (sizeof (NODE));
  temp->bin_num = conversion[num];//Need help with this line


  temp->next = NULL;

  if (head == NULL)
    {

      head = temp;

    }

  else
    {

      temp->next = head;

      head = temp;

    }

}


//This is not the entire code

Answer 1

So conversion is a char * ; it's value when not using an index (within [] ) is a pointer at the beginning of the character array.

If temp->bin_num is also char * you can pass a pointer to a specific position into the conversion array using:

temp->bin_num = conversion + num;

Be aware though that you will now have a pointer to the remainder of the character array. That pointer will have to be de-referenced on use, ex: printf("%c\n", *temp->bin_num); .