如何使用 WriteableBitmap 绘制一个矩形？

Question

I created a WPF project which just includes an Image control.

<Image 
  x:Name='img'
  Width='256'
  Height='256'
  MouseDown='img_MouseDown' />

My goal is to click the image and draw a 10 pixel side square , of white color, at the specific position where the click happened.

At the begining I tried to draw 1 pixel sized squares and worked as expected.

Here is that code:

 public partial class MainWindow : Window
    {
        WriteableBitmap wb;

        public MainWindow()
        {
            InitializeComponent();
            wb = new WriteableBitmap(256, 256, 96d, 96d, PixelFormats.Bgr24, null);
            img.Source = wb;
        }

        private void img_MouseDown(object sender, MouseButtonEventArgs e)
        {
            Point p = e.GetPosition(img);

            Int32Rect rect = new Int32Rect((int)p.X, (int)p.Y, 1, 1);
            int stride = wb.PixelWidth * wb.Format.BitsPerPixel / 8;
            byte[] buffer = { 255, 255, 255 };
            wb.WritePixels(rect, buffer, stride, 0);
        }
    }

Now that I want to draw a 10 pixel size square I am initializing the rect with 10 pixels width and height,

Int32Rect rect = new Int32Rect((int)p.X, (int)p.Y, 10, 10);

,but WritePixels() throws an Exception saying " Buffer size is not sufficient. " Out of desperation I've changed the buffer to have 10 size but still getting the same error.

What is the problem here?

Answer 1

The stride argument is meant to be that of the input buffer, ie 3 x 10 here:

var width = 10;
var height = 10;
var stride = (width * wb.Format.BitsPerPixel + 7) / 8;
var rect = new Int32Rect((int)p.X, (int)p.Y, width, height);
var buffer = Enumerable.Range(0, stride * height).Select(i => (byte)255).ToArray();
wb.WritePixels(rect, buffer, stride, 0);