我有一个带有列表的 pandas 列。 对包含来自同一列的至少一个公共元素的行进行分组

Question

I have pandas df with 1 column with lists. I would like to group all lists which have at least one element in common.

Input Df :
> 
    Category
 0  [IAB19, IAB81, IAB82]
 1  [IAB25, IAB27]
 2  [IAB19, IAB20]
 3  [IAB22, IAB55, IAB56, IAB58]
 4  [IAB81, IAB89]
 5  [IAB82, IAB95]

i want to find out if any codes in df['Category'] is present in any other row of df['Category'].

And if yes, I would want to merge those lists sharing at least 1 common element.

Expected Output:

    Category
 0  [IAB19, IAB81, IAB82, IAB20, IAB89, IAB95]
 1  [IAB25, IAB27]
 2  [IAB22, IAB55, IAB56, IAB58]

Any thoughts?

Answer 1

This is a hidden network problem, so we can try networkx , but before that you may need to explode the whole list columns to single row item (function available after pandas 0.25 )

import networkx as nx
df['Key']=df.index
df=df.explode('Category')
G=nx.from_pandas_edgelist(df, 'Category', 'Key')
l=list(nx.connected_components(G))
L=[dict.fromkeys(y,x) for x, y in enumerate(l)]
d={k: v for d in L for k, v in d.items()}
s=df.groupby(df.Key.map(d)).Category.apply(set)
s
Key
0    {IAB89, IAB82, IAB19, IAB95, IAB81, IAB20}
1                                {IAB27, IAB25}
2                  {IAB55, IAB56, IAB22, IAB58}
Name: Category, dtype: object