对不在列表中的列进行分组和求和

Question

I have a df data frame with columns with the following pattern: #number - letter and I want to add in a new column other that makes the sum of the columns that are not in letter_table1 and letter_table2 :

TEXT, A, B, C, D, E, F, G, H, I
a,1,1,1,2,2,2,3,3,3
b,1,1,1,2,2,2,3,3,3
c,1,1,1,2,2,2,3,3,3
d,1,1,1,2,2,2,3,3,3
e,1,1,1,2,2,2,3,3,3
f,1,1,1,2,2,2,3,3,3
g,1,1,1,2,2,2,3,3,3
h,1,1,1,2,2,2,3,3,3
i,1,1,1,2,2,2,3,3,3
j,1,1,1,2,2,2,3,3,3

for instance:

tableau_lettres1 = [H]
tableau_lettres2 = [I, J]

How can I do that? For the moment I have tried:

        df_sum['others'] = df.loc[:,~df.isin(tableau_lettres1, tableau_lettres2)].sum(axis=1)

as well as:

        df_sum['others'] = df.loc[:,df.drop(tableau_lettres1, tableau_lettres2)].sum(axis=1)

Answer 1

As tableau_lettres1, tableau_lettres2 are lists, you need to join them to one list, and get the other column names like:

df_sum['others'] = df[[col for col in df.columns.tolist() if col not in tableau_lettres1 + tableau_lettres2]].sum(axis=1)