如何使用 `subprocess` 模块执行 __name__== '__main__ ' * without* 下面的 python 代码？

Question

I have a python script with the form

...
if __name__=='__main__':
   parser = argparse.ArgumentParser()
   #code

From another python script, how can I execute the code below __name__ == '__main__' without using the subprocess module?

[Edit] In addition, my python script takes input parameters with the argparse module. I also need to pass parameters when executing the code below the __name__ part.

Answer 1

you might be able to get away with:

import sys
imp_new_module = type(sys)
new_module = imp_new_module(module_name)
new_module.__dict__['__name__'] = '__main__'
exec(open(scriptname).read(), new_module.__dict__)

But you shouldn't do it... :)

(updated question)

Oh, since you're at it you can also import os, sys and then update sys.argv to what you want to pass on (eg sys.argv = [os.path.abspath('file.py'), '--my', 'par']) ... did I mention that you really shouldn't?

Seriously, if you have control over the script that you are calling you might want to put the code under if __name__ == '__main__': in a function

def main(argv):
    ... 
    parser.parse_args(argv)
    ...

if __name__ == '__main__':
    main(sys.argv)

Or better still define a function (or functions, object) in the script that provides an API better suited to be called from a script, which is also called from __name__ == '__main__' based on what is found in sys.argv .