通过字符串自动化 python 脚本？

Question

let say that thoses python objects below are locked we just cannot change the code, all we can is writing right after it. i know it's aweful. but let say that we are forced to work with this.

Name01 = "Dorian"
Name02 = "Tom"
Name04 = "Jerry"
Name03 = "Jessica"
#let say that there's 99 of them

How to print the name of each and single one of them (99) witouth repetition?

from my noob perspective. the ideal way to resolve this case witouth repetition is using the same logic that we have with strings.

Because name => Name+index so it can be really easy to iterate with them.

so somewhat a code that work in the same logic of the totally fictive one below:

for i in range (1,100):
    print(Name+f"{i:02d}")

for i in range (1,100):
     string_v_of_obj = "Name" + str(f"{i:02d}")
     print(func_transform_string_to_code(string_v_of_obj))

maybe something like that is possible.

for python_object in script_objects:
    if Name in python_object:
       print(python_object)

Answer 1

This could do the trick:

Name01 = "Dorian"
Name02 = "Tom"
Name04 = "Jerry"
Name03 = "Jessica"

vars = locals().copy()
for i in vars:
    if 'Name' in i:
        print((i, eval(i)))

alternative in one line:

Name01 = "Dorian"
Name02 = "Tom"
Name04 = "Jerry"
Name03 = "Jessica"

print([(i, eval(i)) for i in locals().copy() if "Name" in i])

Answer 2

You can access the global variables through globals() or if you want the local variables with locals() . They are stored in a dict . So

for i in range (1,100):
    print(locals()[f"Name{i:02d}"])

should do what you want.

Answer 3

You can use exec:

Name01 = "Dorian"
Name02 = "Tom"
Name04 = "Jerry"
Name03 = "Jessica"
for i in range(1,5):
    num = f"{i:02d}" # python3.6+
    num = "{0:02d}".format(i) # python 3.x
    num = "%02d"%i # python 2
    exec('print(Name'+num+')')

Answer 4

Using this code, as per requirement, you will just print names without printing duplicates:

Name01 = "Dorian"
Name02 = "Tom"
Name03 = "Tom"
Name04 = "Jerry"
Name05 = "Jessica"
Name06 = "Jessica"

vars = locals().copy()

names = []

for variable in vars:
    # This will make sure that we are only
    # using variables having 'Name' in their names
    if 'Name' in variable: 
        # Getting the variable's value
        value = eval(variable)
        # If the value is not duplicate
        if value not in names:
            # Append it to our final names list
            names.append(value)

for name in names:
    print (name)

Output

Dorian
Tom
Jessica
Jerry

Explanation

The locals() function returns a dictionary containing the variables defined in the local namespace. Calling locals() in the global namespace is same as calling globals() and returns a dictionary representing the global namespace of the module.

Answer 5

use eval()

>>> Name01 = "Dorian"
>>> Name02 = "Tom"
>>> Name04 = "Jerry"
>>> Name03 = "Jessica"
>>> for i in range(1, 100):
...   print(eval('Name%02d'%i))
... 
Dorian
Tom
Jessica
Jerry

incase if you are using 3.7+ you can go with f string

f"Name{i:02d}"