[英]Automate a python script through strings?
假设下面的那些 python 对象被锁定,我们无法更改代码,我们只能在它之后编写。 我知道这太可怕了。 但是可以说我们被迫处理这个问题。
Name01 = "Dorian"
Name02 = "Tom"
Name04 = "Jerry"
Name03 = "Jessica"
#let say that there's 99 of them
如何在不重复的情况下打印每个和单个(99)的名称?
从我的菜鸟的角度来看。 在不重复的情况下解决这种情况的理想方法是使用与字符串相同的逻辑。
因为 name => Name+index所以很容易用它们进行迭代。
所以有点像下面完全虚构的代码一样的代码:
for i in range (1,100):
print(Name+f"{i:02d}")
for i in range (1,100):
string_v_of_obj = "Name" + str(f"{i:02d}")
print(func_transform_string_to_code(string_v_of_obj))
也许这样的事情是可能的。
for python_object in script_objects:
if Name in python_object:
print(python_object)
这可以解决问题:
Name01 = "Dorian"
Name02 = "Tom"
Name04 = "Jerry"
Name03 = "Jessica"
vars = locals().copy()
for i in vars:
if 'Name' in i:
print((i, eval(i)))
一行中的替代方案:
Name01 = "Dorian"
Name02 = "Tom"
Name04 = "Jerry"
Name03 = "Jessica"
print([(i, eval(i)) for i in locals().copy() if "Name" in i])
您可以通过globals()
访问全局变量,或者如果您想要使用locals()
访问局部变量。 它们存储在dict
中。 所以
for i in range (1,100):
print(locals()[f"Name{i:02d}"])
应该做你想做的。
您可以使用执行:
Name01 = "Dorian"
Name02 = "Tom"
Name04 = "Jerry"
Name03 = "Jessica"
for i in range(1,5):
num = f"{i:02d}" # python3.6+
num = "{0:02d}".format(i) # python 3.x
num = "%02d"%i # python 2
exec('print(Name'+num+')')
使用此代码,根据要求,您将只打印名称而不打印重复项:
Name01 = "Dorian"
Name02 = "Tom"
Name03 = "Tom"
Name04 = "Jerry"
Name05 = "Jessica"
Name06 = "Jessica"
vars = locals().copy()
names = []
for variable in vars:
# This will make sure that we are only
# using variables having 'Name' in their names
if 'Name' in variable:
# Getting the variable's value
value = eval(variable)
# If the value is not duplicate
if value not in names:
# Append it to our final names list
names.append(value)
for name in names:
print (name)
Output
Dorian
Tom
Jessica
Jerry
解释
locals() function 返回一个字典,其中包含在本地命名空间中定义的变量。 在全局命名空间中调用 locals() 与调用 globals() 相同,并返回一个表示模块全局命名空间的字典。
使用eval()
>>> Name01 = "Dorian"
>>> Name02 = "Tom"
>>> Name04 = "Jerry"
>>> Name03 = "Jessica"
>>> for i in range(1, 100):
... print(eval('Name%02d'%i))
...
Dorian
Tom
Jessica
Jerry
如果您使用的是 3.7+,则可以使用f string
go
f"Name{i:02d}"
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