伪造一个非静态 class 的 static 方法

Question

I have a non-static class with a static method that I want to shim it.

public class MyClass
{
    static MyClass()
    {
        //do constructor things
    }
    public static void MyMethod(string str)
    {
        //do something
    }
}

This static method is called from some part of the code I want to test ( MyClass.MyMethod("some string") ), but I'm not interested on MyMethod behavior. I need to shim it. My try is:

MyClassNamespace.Fakes.ShimMyClass.MyMethod = ("some string") => {};

But MyMethod is missing, I believe because the class is not static.

How can I shim it like it was a static class? I have read that it's possible to shim the Contructor and simulate some methods, and maybe that is a better choice, but I don't know how to do it.

Answer 1

You need to define the Shim on AllInstances

MyClassNamespace.Fakes.ShimMyClass.AllInstances.MyMethodString = ("some string") => {};

If you notice in above code the name of method in generated shim is with parameter type (that's the way Shims are generated).

Answer 2

I'm not sure for 100% what you mean, but it looks like you want to store an static action.

In my example you assign a lambda expression to the static field. The instances can call this Action:

public class MyClass
{
    public static Action<string> LogMehod;

    public void Log(string s)
    {
        // call the static log method if it is assigned.
        if(LogMehod != null)
            LogMehod(User + ": " + s);
    }
    public string User {get;set;}
}

class Program
{
    static Main()
    {
        // assign an lambda expression, which displays the passed string.
        MyClass.LogMehod = s =>
        {
            Console.WriteLine(s);
        }

        // create an instance of MyClass
        var user1 = new MyClass();
        user1.User = "User1";
        user1.Log("bla");

        var user2 = new MyClass();
        user2.User = "User2";
        user2.Log("also bla");

        Console.ReadLine();
    }
}

Gives:

User1: bla
User2: also bla