[英]calling functions python from outside
I have small a python script looking something like this:我有一个小的 python 脚本,看起来像这样:
def number1():
x = 1
open_numbers = []
open_numbers.append(x)
return open_numbers
def myfunction(open_numbers):
y = 1
open_numbers.append(y)
I would like to call the myfunction in the the end of the script.我想在脚本末尾调用 myfunction 。 Using
使用
myfunction()
But it keeps telling me missing 1 required positional argument: 'open_numbers'
但它一直告诉我
missing 1 required positional argument: 'open_numbers'
Tried passing the argument and got name 'open_numbers' is not defined
尝试传递参数并得到
name 'open_numbers' is not defined
I plan to add more functions later and run them the same way我计划稍后添加更多功能并以相同的方式运行它们
function(arg)
function2(arg)
function3(arg)
First of all, your code was not properly indented.首先,您的代码没有正确缩进。 I have corrected that.
我已经纠正了。
The function myfunction
takes in a list
( open_numbers
) as input and should return it as well. myfunction
接受一个list
( open_numbers
)作为输入,也应该返回它。
I have passed in the output of number1()
as the input to myfunction()
.我已经传入
number1()
的 output 作为myfunction()
的输入。 This should create a list: [1, 1]
.这应该创建一个列表:
[1, 1]
。 And that's what it did.这就是它所做的。
def number1():
x = 1
open_numbers = []
open_numbers.append(x)
return open_numbers
def myfunction(open_numbers):
y = 1
open_numbers.append(y)
return open_numbers
myfunction(number1())
Output : Output :
[1, 1]
you need to pass in an object to your function.您需要将 object 传递给您的 function。 you can call your function with an empty list if you want:
如果需要,您可以使用空列表调用 function:
a = []
myfunction(a)
You might want to define default parameter, and return the updated value您可能想要定义默认参数,并返回更新后的值
def myfunction(open_numbers = []):
y = 1
open_numbers.append(y)
return open_numbers
Then you can call it with passing parameter myfunction([1])
or without myfunction()
然后您可以使用传递参数
myfunction([1])
或不myfunction()
来调用它
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