从 python 字典中调用函数

Question

How to call multiple functions based on the input values. We can implement this with dictionary without using if-else by below:

def fun1(a, b, c) :
 ....
def fun2() :
 ....
def fun3() :
.....


dict{1 : fun1,
     2 : fun2,
     3 : fun3}

dict[1](input arguments)

But if the input parameters of different functions are different how can we pass input parameters without if-else. The idea of this approach is to avoid conditions and directly call functions based on input values.

Answer 1

You can try *args method

def fun1(a, b, c):
    print("1", a, b, c)

def fun2(a):
    print("2", a)

def fun3():
    print("3")

fun_map = {
    1 : fun1,
    2 : fun2,
    3 : fun3
}

sample calls

inputs = (1,2,3)
fun_map[1](*inputs)
# output: 1 1 2 3

inputs = (1, )
fun_map[2](*inputs)
# output: 2 1

inputs = ()
fun_map[3](*inputs)
# output: 3