检查是否有任何数字单独重复超过 N 次

Question

What I want to check is if there is any number repated more than 5 times with a regex.

I have looked through some other questions, and the suggestion they make is this one /([0-9]{5}\1)/ . But this one matches any 5 numbers together.

What I want to achieve with this regex is finding if, for example, number 1 is repeated 5 times, number 2, number 3 and so on.

Is there any way to achieve this via regex or should I make a loop for all values?

112113 false

911111 true

112111 false

222223 true

Answer 1

Your pattern ([0-9]{5}\1) uses a backreference to a group that does not exist yet.

In Javascript you will match 5 consecutive digits as according to the documentation stated at the link to the backreference

According to the official ECMA standard, a backreference to a non-participating capturing group must successfully match nothing..

You could update your pattern to put the capturing group around matching a single digit and then repeat that 4 times to match 5 repeated digits.

([0-9])\1{4}

Regex demo

Answer 2

You can simply use filter. It is faster than regex. In the function input the number, the number whose repentance has to be calculated and the number of times the repetition has to be found. Convert the number to a string and split it into an array. Apply filter and for the occurrence of the number. It will return an array. If the length of the array is equal to the number of repentance than return true else false

 var n = 1; var num = 1123231121; var comp = 5 function a(n, num, comp) { console.log(String(num).split('').filter(function(e) { return e == n }).length == comp) } a(n, num, comp)

Answer 3

if (/[^\d]\d{5}[^\d]/.test(num)) {
    //Test passed
}

this would work as a regex.

 var inputs = [ '112113', '911111', '112111', '222223' ]; inputs.forEach(function(input) { if (/[^\d]\d{5}[^\d]/.test(input)) { console.log(input); } });