[英]Regular expression to check any character in more than two times
I'm looking for a simple regular expression to match same character in the string more than two times likes following in java script.我正在寻找一个简单的正则表达式来匹配字符串中的相同字符两次以上,就像在 java 脚本中一样。 (Number 1 is three times) 112561
(数字1是三倍)112561
You could check if a group is more than tow times in the array.您可以检查一个组在数组中是否超过两次。
console.log(/(.).*\1.*\1/.test('12561')); console.log(/(.).*\1.*\1/.test('112561'));
The following regex can be used for this purpose:以下正则表达式可用于此目的:
.*(.).*\1.*\1.*
This will check if a character is repeated more than 2 times in a string.这将检查一个字符是否在字符串中重复超过 2 次。 Note that this also does not use
*
which is a cause for performance issues in JavaScript.请注意,这也不使用
*
,这是 JavaScript 中性能问题的原因。
console.log(/.+?(.)((?:.)+?\1){1,}/.test('abcZdefZghiZ')) console.log(/.+?(.)((?:.)+?\1){1,}/.test('112561')) console.log(/.+?(.)((?:.)+?\1){1,}/.test('12561'))
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