Javascript 正则表达式构造函数匹配字符串，并忽略 null、未定义或空字符串

Question

I'm trying to add regular expressions to only match non-null values. What I've tried below breaks the application as there are some names , ages , and genders that are undefined and null in the database. I'm trying to find a regex that will ignore the null, undefined, or empty values in the database, and only match on values that exist.

I understand ^(?.\s*$).+ will match any string that contains at least one non-space character. But I'm struggling with how to add this to the action.payload (the string I'm matching against).

case FILTER_USERS:
    return {
        ...state,
        user_info: state.userArr.filter(user => {
            const regex = new RegExp(`${action.payload}`, "gi");
            return (
              user.name.match(regex)
              || user.age.match(regex)
              || user.gender.match(regex)
            );
        })
    };

I know this is very incorrect, but this is what I tried: const regex = new RegExp(`(^?)${action.payload}(.\s*$),+)`; "gi"); const regex = new RegExp(`(^?)${action.payload}(.\s*$),+)`; "gi");

Any help would be appreciated - thank you!

Answer 1

Placing (?=^[^\s]$) in front of your regex will assert there's at least one non-whitespace character in the match.

If you're already checking to make sure that the string isn't only whitespace, why not use if(${action.payload}) instead? This will detect both empty strings and null strings, since they're both falsey.