来自 RGB byte[] 数组的 BufferedImage

Question

I have a byte[] array with RGB values. I would like to create BufferedImage without setting the pixels one by one, as the image can be big. I've found the following snippet:

        byte[] frame = ...;
        BufferedImage img = new BufferedImage(width, height, BufferedImage.TYPE_3BYTE_BGR);
        img.setData(Raster.createRaster(img.getSampleModel(), new DataBufferByte(frame, frame.length), new Point() ) );

Which does work nice, but there is a small issue;-) TYPE_3BYTE_BGR is expecting bytes in reverse order.

So the questions are:

1. Is it possible to load my array somehow without actually creating a new byte array with expected ordering?
2. If its not possible, is there any better way than for loop to copy data from RGB format to BGR?

Answer 1

Try this code

BufferedImage img = create3ByteRGBImage(int width, int height, new int[] {8, 8, 8},
                                     new int[] {0, 1, 2});    

private BufferedImage create3ByteRGBImage(width, height, int[] nBits, int[] bOffs) {
            ColorSpace cs = ColorSpace.getInstance(ColorSpace.CS_sRGB);
            ColorModel colorModel =
                new ComponentColorModel(cs, nBits,
                                        false, false,
                                        Transparency.OPAQUE,
                                        DataBuffer.TYPE_BYTE);
            WritableRaster raster =
                Raster.createInterleavedRaster(DataBuffer.TYPE_BYTE,
                                               width, height,
                                               width*3, 3,
                                               bOffs, null);
            return new BufferedImage(colorModel, raster, false, null);
        }