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Pandas- 填充 nans 直到第一个非 NULL 值

[英]Pandas- Fill nans up until first non NULL value

I have a dataframe like我有一个 dataframe 之类的

A    B    C
1    nan  nan
2    nan  5
3    3    nan
4    nan  nan

How do I only fill the NULLs (with 0) for each series up until the first non NULL value, leading to如何仅填充每个系列的 NULL(使用 0)直到第一个非 NULL 值,导致

A    B    C
1    0    0
2    0    5
3    3    nan
4    nan  nan

Bit of a trick using pandas.DataFrame.ffill with notna and where :使用带有pandas.DataFrame.ffillwhere的 pandas.DataFrame.ffill notna技巧:

df.where(df.ffill().notna(), 0)

Or using pandas.DataFrame.interpolate :或使用pandas.DataFrame.interpolate

df.interpolate('zero', fill_value=0, limit_direction='backward')

Output: Output:

   A    B    C
0  1  0.0  0.0
1  2  0.0  5.0
2  3  3.0  NaN
3  4  NaN  NaN

This would be done using where or mask .这将使用wheremask来完成。

df.mask(df.notna().cumsum().eq(0), 0)
# or,
df.where(df.notna().cumsum().ne(0), 0)

   A    B    C
0  1  0.0  0.0
1  2  0.0  5.0
2  3  3.0  NaN
3  4  NaN  NaN

Many ways to skin a cat here:-)这里有很多剥猫皮的方法:-)

Since 0 + nan is nan this works:由于 0 + nan 是 nan 这有效:

xf = df.fillna(0) + df.bfill()*0

Good Answers above.上面的好答案。 Alternately, if you want to do it for a specific column:或者,如果您想为特定列执行此操作:

df[columnName][:df[columnName].first_valid_index()].fillna(0, inplace=True)

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