如何 append 列出 Python 中字典中的元素

Question

I reviewed those posts: append list inside dictionary with update and Append element to smallest list in dictionary of lists . They didn't help help me. I wanted to do something like that: there was a result = {} and spl = input().split(' ') , I did something and it turned into result = {'text': [1, 2]} (for example). How to do this?

I tried to make a thing like in the first link: result.update({'text': result['text'] + [1, 2]}) , but it did not worked. I also tried thing from the second link:

result = {'text': []}
result['text'].append(1, 2)

but it gave me an error AttributeError: 'str' object has no attribute 'append' . The real code part until the intended part is down below.

The code:

def checkThru(txt, wordsDesc=1, countMoreMost=False, indexInOutput=False):
    result = {}
    spl = txt.split(' ')
    badChars = ['?', ',', '.', '!',]
    wordam = list(range(0, wordsDesc))

    for lol in range(len(spl)):
        for sublol in badChars:
             spl[lol] = spl[lol].replace(sublol, "")

    for i in spl:

        iinspl = spl.index(i)

        if indexInOutput == True:

            if i == 'are' or i == 'am' or i == 'is' or i == 'were' or i == \
            'was' or i == 'will' or i == 'shall':

                if spl[iinspl + 1] == 'a' or spl[iinspl + 1] == 'an' or \
                spl[iinspl + 1] == 'the':

                    if countMoreMost == False:

                        if spl[iinspl + 2] == 'more' or spl[iinspl + 2] == 'most':

                            result.update({iinspl-1: []})

                            for add in wordam:

                                result.update({spl[iinspl-1].append(iinspl+3+add)}) #???(Here's where the error says something is wrong.)
#Actually, spl[iinspl-1] is going to be a list, because of the line <<result.update({iinspl-1: []})>>

Traceback:

Traceback (most recent call last):
  File "D:\python\I MADE A MODULE!!! indeX.py", line 16, in <module>
    print(indeX.checkThru('Hello, I am David. My sister is the most Ann babe', 1, False, True))
  File "C:\Users\Danil\AppData\Local\Programs\Python\Python37-32\lib\indeX.py", line 287, in checkThru
    result.update({spl[iinspl-1].append(iinspl+1+add)})
AttributeError: 'str' object has no attribute 'append'

I wanted it to make a dictionary of characteristics. For example:

print(checkThru('Hi, I am David, and my sister is Ann!'))

>>> {'I': ['David'], 'sister': ['Ann']}

Answer 1

Your code:

result = {'text': []}
result['text'].append(1, 2)

Shouldn't give AttributeError: 'str' object has no attribute 'append' unless you define the value of result['text'] as a string before trying to append.

However, append doesn't take two arguments like that. If you want to add 1 and 2 to the list, you would do one of:

result = {'text': []}
result['text'].append(1)
result['text'].append(2)

print(result)

prints:

{'text': [1, 2]}

or

result = {'text': []}
result['text'] += [1, 2]

print(result)

prints:

{'text': [1, 2]}

Answer 2

result = {'text': []} result['text'].append(1, 2)

Will give

TypeError: append() takes exactly one argument (2 given) because append takes only one argument. Not the one you have mentioned.

One way to go is append element by element if you dont want to return a list of list. result = {'text':[]} result['text'].append(1) result['text'].append(2) result {'text': [1, 2]} will give the desired result

Or use update instead. The syntax seems fine:

result.update({'text': [1, 2]}) result {'text': [1, 2]}

Having said that, After a quick review of the code:

1. All the decisions are triggered via if conditions (only if-nested blocks) so all should be True such that your result dictionary gets modified please review that once.
2. Default parameters to the function start with False the check the code does is against True hence it will not the program will exit after first check itself.

{Note: A dry run of the code will print statements can help you get the logic right}

Answer 3

The second-link thing you posted:

result = {'text': []}
result['text'].append(1, 2)

...will work. The error you're getting is because of what it says - you're trying to run append on a string.

Your spl list is a list of strings, resulting from txt.split() . Your code:

spl[iinspl-1].append()

...will therefore always be trying to append to a string, which (as you're finding) doesn't work.

I think probably in that bit of code you mean to be appending to result , not spl ?

EDIT: Or else you want something like:

result[spl[iinspl-1]].append(iinspl+3+add))

Might be update rather than append, depending on exactly what's in there and what you want out.