我想从 csv 文件中提取字符串的某些部分

Question

I have vast number of columns containing this kind of data:

DE-JP-202/2066/A2@qwier.cu/68
NL-LK-02206/2136/A1@ozmmfts.de/731
OM-PH-31303222/3671/Z1@jtqy.ml/524

I would like to extract string between '@' and '.'and between '.'and '/' into two separete colums.

Like:

txt 1      txt 2
qwier       cu
ozmmft      de
jtqy        ml

Tried:

x = dane.str.extract(r'@(?P<txt1>\d)\.(?P<txt2>[ab\d])/')

But doesn't work

Answer 1

If you want to get 2 capturing groups, you could use 2 negated character classes .

In the first group match 1+ times any char except a dot [^.]+

In the second group match 1+ times any char except a forward slash [^/]+

@(?P<txt1>[^.]+)\.(?P<txt2>[^/]+)/

Regex demo

Answer 2

If the formatting of your strings all have only 1 @ and 1 . . You can do the following:

s = 'DE-JP-202/2066/A2@qwier.cu/68'

column1 = s.split('@')[1].split('.')[0]

column2 = s.split('@')[1].split('.')[1].split('/')[0]