如何在结构内将 char[] 分配给 null

Question

I m trying to assign null to char name[] inside the struct; however, it not working

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
#include <string.h>

#define name_size  30   
#define bloc_entry_number  20   
#define file_list_number 10
#define direction_list_number 10

struct File { 
    char name[name_size]; 
    int block_entry[bloc_entry_number]; 
};

struct Direction{    
    char name[name_size];
    int current_index;
    int previous_index;

    struct File* file_list[file_list_number]; 
    int file_list_tracking[file_list_number]; 

    struct Direction* next_entry_direction[direction_list_number]; 
    int next_entry_direction_tracking[direction_list_number];
};

struct Block{
    int index; 
    int size_remain; 
};

int main(){
    struct Direction *dir = (struct Direction*) malloc(sizeof(struct Direction));

    for (int i = 0; i < 10; i ++ ){
        dir->next_entry_direction[i]->name[0] = '\0'; // error occur here
        printf("%s",dir->next_entry_direction[i]->name);// error occur here;
    }
    return 0;
}

im not able to assign NULL to char name[]; how can i fix it? i have already try name[0] = '\0', name = NULL, strcpy(name,NULL)

Answer 1

You cannot set it to NULL. It's an array and not a pointer. What you can do is this:

dir->next_entry_direction[i]->name[0] = '\0';